Java多线程，循环打印”ABC”10次

面试题

思路

3个线程A,B,C分别打印三个字母，每个线程循环10次，首先同步，如果不满足打印条件，则调用wait()函数一直等待；之后打印字母，更新state，调用notifyAll()，进入下一次循环。

代码

public class printABC {
    private static int state = 0;
    public static void main(String[] args) {
        final printABC t = new printABC();
        Thread A = new Thread(new Runnable() {
            public void run() {
                // 设定打印10次
                for (int i = 0; i < 10; i++) {
                    synchronized (t) {
                        // 如果不满足A的打印条件，则调用wait，一直阻塞
                        while (state % 3 != 0) {
                            try {
                                t.wait();
                            } catch (InterruptedException e) {
                                e.printStackTrace();
                            }
                        }
                        // 执行到这里，表明满足条件，打印A，设置state
                        // 调用notifyAll方法
                        System.out.print("A");
                        state++;
                        t.notifyAll();
                    }
                }
            }
        });
        Thread B = new Thread(new Runnable() {
            public void run() {
                for (int i = 0; i < 10; i++) {
                    synchronized (t) {
                        while (state % 3 != 1) {
                            try {
                                t.wait();
                            } catch (InterruptedException e) {
                                e.printStackTrace();
                            }
                        }
                        System.out.print("B");
                        state++;
                        t.notifyAll();
                    }
                }
            }
        });
        Thread C = new Thread(new Runnable() {
            public void run() {
                for (int i = 0; i < 10; i++) {
                    synchronized (t) {
                        while (state % 3 != 2) {
                            try {
                                t.wait();
                            } catch (InterruptedException e) {
                                e.printStackTrace();
                            }
                        }
                        System.out.println("C");
                        state++;
                        t.notifyAll();
                    }
                }
            }
        });
        A.start();
        B.start();
        C.start();
    }
}

2017年07月31日 更新

最近看到了原来写的博客，觉得当时写得并不是很好，重新写了一下，记录之。

package test;
public class PrintABC {
    private static final int PRINT_A = 0;
    private static final int PRINT_B = 1;
    private static final int PRINT_C = 2;
    private static class MyThread extends Thread {
        int which; // 0：打印A；1：打印B；2：打印C
        static volatile int state; // 线程共有，判断所有的打印状态
        static final Object t = new Object();
        public MyThread(int which) {
            this.which = which;
        }
        @Override
        public void run() {
            for (int i = 0; i < 10; i++) {
                synchronized (t) {
                    while (state % 3 != which) {
                        try {
                            t.wait();
                        } catch (InterruptedException e) {
                            e.printStackTrace();
                        }
                    }
                    System.out.print(toABC(which)); // 执行到这里，表明满足条件，打印
                    state++;
                    t.notifyAll(); // 调用notifyAll方法
                }
            }
        }
    }
    public static void main(String[] args) {
        new MyThread(PRINT_A).start();
        new MyThread(PRINT_B).start();
        new MyThread(PRINT_C).start();
    }
    private static char toABC(int which) {
        return (char) ('A' + which);
    }
}