@EtoDemerzel
2017-11-29T12:54:22.000000Z
字数 5551
阅读 1998
机器学习 吴恩达这周学习异常监测, 第一部分完成对一个网络中故障的服务器的监测。第二部分使用协同过滤来实现一个电影推荐系统。
监测服务器工作状态的指标:吞吐量(throughput)、延迟(latency)。
我们有 的无标签数据集,这里认为其中绝大多数都是正常工作的服务器,其中少量是异常状态。
先通过散点图来直观判断。

对数据的分布情况选择一个模型。
高斯分布的公式如下:
其中 是平均值,是标准差。
根据如下公式计算高斯分布的参数:
完成estimateGaussian.m如下:
function [mu sigma2] = estimateGaussian(X)%ESTIMATEGAUSSIAN This function estimates the parameters of a%Gaussian distribution using the data in X% [mu sigma2] = estimateGaussian(X),% The input X is the dataset with each n-dimensional data point in one row% The output is an n-dimensional vector mu, the mean of the data set% and the variances sigma^2, an n x 1 vector%% Useful variables[m, n] = size(X);% You should return these values correctlymu = zeros(n, 1);sigma2 = zeros(n, 1);% ====================== YOUR CODE HERE ======================% Instructions: Compute the mean of the data and the variances% In particular, mu(i) should contain the mean of% the data for the i-th feature and sigma2(i)% should contain variance of the i-th feature.%mu = mean(X);sigma2 = var(X,1); % choose the way to divide by N rather than N-1% =============================================================end
完成之后,脚本文件会执行绘制等高线的操作,即得到如下图像:

以 为临界值, 的情况被认为是异常状况。
通过交叉验证集来选择这样的 。
交叉验证集中的数据是带标签的。根据之前学到的 来评价选择的优劣。
其中 分别代表true positive,false positive, false negative。
function [bestEpsilon bestF1] = selectThreshold(yval, pval)%SELECTTHRESHOLD Find the best threshold (epsilon) to use for selecting%outliers% [bestEpsilon bestF1] = SELECTTHRESHOLD(yval, pval) finds the best% threshold to use for selecting outliers based on the results from a% validation set (pval) and the ground truth (yval).%bestEpsilon = 0;bestF1 = 0;F1 = 0;stepsize = (max(pval) - min(pval)) / 1000;for epsilon = min(pval):stepsize:max(pval)% ====================== YOUR CODE HERE ======================% Instructions: Compute the F1 score of choosing epsilon as the% threshold and place the value in F1. The code at the% end of the loop will compare the F1 score for this% choice of epsilon and set it to be the best epsilon if% it is better than the current choice of epsilon.%% Note: You can use predictions = (pval < epsilon) to get a binary vector% of 0's and 1's of the outlier predictionsprediction = (pval < epsilon);tp = sum((prediction == 1) & (yval == 1)); % true positivefp = sum((prediction == 1) & (yval == 0)); % false positivefn = sum((prediction == 0) & (yval == 1)); % false negativeprec = tp / (tp + fp); % precisionrec = tp / (tp + fn); % recallF1 = 2 * prec * rec/ (prec + rec); % F1% =============================================================if F1 > bestF1bestF1 = F1;bestEpsilon = epsilon;endendend
按照选定的 ,判断异常情况如下图:

对上述函数,换用更高维的数据集。(11 features)
与之前2维的情况并没有什么区别。
对关于电影评分的数据集使用协同过滤算法,实现推荐系统。
Datasets来源:MoiveLens 100k Datasets.
对矩阵可视化:
作为对比,四阶单位矩阵可视化情况如下:

矩阵 (大小为num_movies num_users);
矩阵 ( 表示电影 被用户 评分过).
整个2.2都是对cofiCostFunc.m的处理。
原文件中提供的代码如下:
function [J, grad] = cofiCostFunc(params, Y, R, num_users, num_movies, ...num_features, lambda)%COFICOSTFUNC Collaborative filtering cost function% [J, grad] = COFICOSTFUNC(params, Y, R, num_users, num_movies, ...% num_features, lambda) returns the cost and gradient for the% collaborative filtering problem.%% Unfold the U and W matrices from paramsX = reshape(params(1:num_movies*num_features), num_movies, num_features);Theta = reshape(params(num_movies*num_features+1:end), ...num_users, num_features);% You need to return the following values correctlyJ = 0;X_grad = zeros(size(X));Theta_grad = zeros(size(Theta));% ====================== YOUR CODE HERE ======================% Instructions: Compute the cost function and gradient for collaborative% filtering. Concretely, you should first implement the cost% function (without regularization) and make sure it is% matches our costs. After that, you should implement the% gradient and use the checkCostFunction routine to check% that the gradient is correct. Finally, you should implement% regularization.%% Notes: X - num_movies x num_features matrix of movie features% Theta - num_users x num_features matrix of user features% Y - num_movies x num_users matrix of user ratings of movies% R - num_movies x num_users matrix, where R(i, j) = 1 if the% i-th movie was rated by the j-th user%% You should set the following variables correctly:%% X_grad - num_movies x num_features matrix, containing the% partial derivatives w.r.t. to each element of X% Theta_grad - num_users x num_features matrix, containing the% partial derivatives w.r.t. to each element of Theta%% =============================================================grad = [X_grad(:); Theta_grad(:)];end
未经过regularization的代价函数如下:
故增加如下代码:
diff = (X * Theta' - Y);vari = diff.^2;J = 1/2 * sum(vari(R == 1));
公式如下:

按照文档里的Tips进行向量化,加入如下代码:
for i = 1: num_movies,X_grad(i,:) = sum(((diff(i,:).* R(i,:))'.* Theta));end;for j = 1: num_users,Theta_grad(j,:) = sum(((diff(:,j).* R(:,j)) .* X));end;
想了一会,发现好像可以更彻底地向量化:
X_grad = diff.* R * Theta;Theta_grad = (diff.*R)' * X;
只需要在上述代码中加入regularization的部分即可。
如下:
J = 1/2 * sum(vari(R == 1)) + lambda/2 * (sum((Theta.^2)(:)) + sum((X.^2)(:)));X_grad = diff.*R*Theta + lambda * X;Theta_grad = (diff.*R)' * X + lambda * Theta;
在脚本文件中填入自己对movie_list.txt中部分电影的评分。
似乎提供的电影都是新世纪以前上映的,因此我没有看过太多。我挑选了如下几部评分:
推荐系统给我推荐了如下电影:

我没有办法判断准不准,因为我一部也没有看过。但随便搜了其中的几部,感觉我可能并不会喜欢。
也许是我提供的样本太小了,也许是这个推荐系统太简陋了吧。