A - Lucky Division

思路：
判断n对4，7这两个数的一位数，两位数，三位数的组合取余是否为零就ok。

#include <stdio.h>
int main()
{
    int n;
    while (scanf("%d",&n) != EOF)
    {
        if (n % 4 == 0 || n % 7 == 0 || n % 44 == 0 || n % 77 == 0 || n % 74 == 0 || n % 47 == 0 || n % 444 == 0 || n % 447 == 0 || n % 477 == 0 || n % 474 == 0 || n % 744 == 0 || n % 777 == 0 || n % 747 || n % 774 == 0)
            printf("YES");
        else
            printf("NO");
    }
    return 0;
}