Bash read lines from file into string array

bash

Best way to do

array=()
# Read the file in parameter and fill the array named "array"
getArray() {
    i=0
    while read line # Read a line
    do
        array[i]=$line # Put it into the array
        i=$(($i + 1))
    done < $1
}
getArray "file.txt"

How to use your array :

# Print the file (print each element of the array)
getArray "file.txt"
for e in "${array[@]}"
do
    echo "$e"
done

The simplest way to read each line of a file into a bash array is this:

#!/bin/bash
IFS=$'\n' read -d '' -r -a lines < /etc/passwd
# Now just index in to the array lines to retrieve each line, e.g.
printf "line 1: %s\n" "${lines[0]}"
printf "line 5: %s\n" "${lines[4]}"
# all lines
echo "${lines[@]}"

split string

#!/usr/bin/env bash
IN="bla@some.com;john@home.com"
arr=$(echo $IN | tr ";" "\n")
for x in $arr
do
    echo "> [$x]"
done

Reference

1 http://stackoverflow.com/questions/11393817/bash-read-lines-in-file-into-an-array
2 http://stackoverflow.com/questions/918886/how-do-i-split-a-string-on-a-delimiter-in-bash